Solving the Equation: (x-3)^2/5 = (4x)^1/5
This article will guide you through the process of solving the equation (x-3)^2/5 = (4x)^1/5. We'll utilize algebraic manipulation and techniques to arrive at the solution.
Step 1: Isolate the Exponents
To simplify the equation, let's get rid of the fractional exponents. We can achieve this by raising both sides of the equation to the power of 5:
[(x-3)^2/5]^5 = [(4x)^1/5]^5
This simplifies to:
(x-3)^2 = 4x
Step 2: Expand and Rearrange
Now, expand the left side of the equation and move all terms to one side:
x^2 - 6x + 9 = 4x
x^2 - 10x + 9 = 0
Step 3: Factor the Quadratic Equation
The equation is now a quadratic equation. We can factor it to find its roots:
(x-9)(x-1) = 0
Therefore, the solutions are:
x = 9 and x = 1
Step 4: Verify the Solutions
It's crucial to check if the solutions we obtained are valid. We can do this by plugging each solution back into the original equation.
For x = 9:
[(9-3)^2/5] = [(4*9)^1/5] [6^2/5] = [36^1/5] 36^1/5 = 36^1/5 (This is true)
For x = 1:
[(1-3)^2/5] = [(4*1)^1/5] [(-2)^2/5] = [4^1/5] 4^1/5 = 4^1/5 (This is true)
Both solutions satisfy the original equation.
Conclusion
The equation (x-3)^2/5 = (4x)^1/5 has two solutions: x = 9 and x = 1. We arrived at these solutions by isolating the exponents, expanding the equation, factoring the quadratic, and finally verifying the solutions.